# SOLUTION: Southern Illinois University Regression Statistic Questions

Attached.

1

Question one
Name of student
Name of professor
Name of course
Name of institution

Question one
I.

2

The ACT beak is damage for 39 students in the grounds set.
The percentage of students who bear a damage ACT beak is almost 39/813
*100%=4.79%≈4.80%.

II.

The mediocre treasure for act is 17848/774=23.059 occasion the mediocre treasure for act0 is
17848/813=21.95.

The mediocre of act0 is inferior than the mediocre treasure for act consequently act0 was created by
replacing damage grounds delay zeros, thus increasing the sum calculate of observations occasion
not changing the sum act beak.
III.

SUMMARY OUTPUT

Regression Statistics
Multiple R
0.78002
R Square
0.608431
Square
0.607948
Standard Error
12.63039
Observations
812
ANOVA
df
Regression

1

Residual

810

Total

811

SS
200780
.6
129216
.7
329997
.3

Coefficien Standar
ts
d Error
Intercept
23

22.1233

2.2865

2.851

0.1461

MS
200780
.6
159.52
68

t Stat
6.1995
34
35.476
77

F
12.317
7

Pvalue
0.029

Significan
ce F
3

Lower
95%
7.228678
2.515456

Upper
95%
13.926
99
2.8101
15

Lower
95.0%
7.2286
78
2.5154
56

Upper
95.0%
13.926
99
2.8101
15

Question one

3

Variable

Coefficient estimate

Standard untruth

Intercept

22.1233

2.2865

act

2.851

0.1461

The F statistics is almost 12.3177 and the corresponding p-treasure is almost: 0.03.
According to the RESET, you decline the null supposition of improve demonstration at the 5%
significance roll. The example of beak on act should be declineed as a outcome.
IV.
SUMMARY OUTPUT
Regression Statistics
Multiple R
0.216988
R Square
0.047084
Square
0.045907
Standard Error
13.14211
Observations
812
ANOVA
df
Regression

1

Residual

810

Total

811

Intercept

SS
6912.4
2...

15 Million Students Helped!