Multiple choices | Mathematics homework help


1.      In a poll, respondents were asked whether they had continually been in a car surroundings. 220 respondents indicated that they had been in a car surroundings and 370 respondents said that they had not been in a car surroundings. If one of these respondents is accidentally clarified, what is the presumption of getting someone who has been in a car surroundings? Round to the undeviating thousandth.A. 0.384 B. 0.380 C. 0.373D. 0.370

                        P(accident) = 220 / (220 + 370) = 0.373

2.      If you flip a invent three spans, the potential developments are HHH, HHT, HTH, HTT, THH, THT, TTH, TTT. What is the presumption of getting at insignificantest one top?

A. 4/9                          B. 5/6                 C. 7/8           D. 5/8

 

            P(at insignificantest one top) = (Number of confederacys following a while one or over H) / (Total                                                                     compute of confederacys)

 

            P(at insignificantest one top) = 7 / 8

 

 

3.      Joe markett 20 cards from a flag 52-card pull-up, and the compute of red cards exceeded the compute of sombre cards by 8. He reshuffled the cards and markett 30 cards. This span, the compute of red cards exceeded the compute of sombre cards by 10. Designate which market is closer to the 50/50 bearing of red/sombre forecasted of impartially markett hands from a impartial pull-up and why.

A. The leading course is closer accordingly 1/10 is farther from 1/2 than is 1/8.

B. The course closer to the speculative 50/50 cannot be decided equaltual the compute of red and sombre cards for each market is dedicated.

C. The cooperate course is closer accordingly 20/30 is closer to 1/2 than is 14/20.

D. The leading course is closer accordingly the destruction floating red and sombre is insignificanter than the destruction in the cooperate course.

 

            1st market: 14 red and 6 sombre     P(red) = 14/20 = 0.70

            2nd market: 20 red and 10 sombre  P(red) = 20/30 = 0.67 < 0.70

 

4.      Suppose you keep an greatly unimpartial die: The presumption of a 6 is 3/8, and the presumption of each other compute is 1/8. If you emit the die 32 spans, how divers twos do you forecast to see?A. 2                        B. 4                            C. 3                             D. 5

                        E(2) = np = 32(1/8) = 4

 

 

5.      A assort consists of 50 women and 82 men. If a novice is accidentally clarified, what is the presumption that the novice is a mother?

A. 32/132 B. 25/66C. 50/132          D. 82/132

 

            P(woman) = 50 / (50 + 82) = 50/132 = 25/66

 

6.      If you flip a invent three spans, the potential developments are HHH, HHT, HTH, HTT, THH, THT, TTH, TTT. What is the presumption that at insignificantest two tops take-place arrangedly?

A. 1/8          B. 3/8           C. 5/8       D. 6/8

 

            P(two arranged H) = (Number of confederacys following a while HH) / (Total compute of                                                                  combinations)

 

            P(two arranged H) = 3/8

 

 

7.      Suppose you buy 1 ticket for $1 out of a lottery of 1000 tickets where the palm for the one alluring ticket is to be $500. What is your forecasted admire?

A. $0.00       B. −$0.40       C. −$1.00        D. −$0.50

 

            E(x) = (1/1000)($500) – 1 = $0.50 - $1 = -$0.50

 

8.      If you flip a invent three spans, the potential developments are HHH, HHT, HTH, HTT, THH, THT, TTH, TTT. What is the presumption of getting at insignificantest two tails?

A. 1/2        B. 2/3           C. 3/4        D. 4/9

 

            P(at insignificantest 2 T) = (Number of confederacys following a while 2 or over T) / (Total compute

                                                of confederacys)

 

            P(at insignificantest 2 T) = 4/8 = ½

 

 

 

9.      A bag contains impure pieces of which one is red, one is bluish, one is unseasoned, and one is yellow. A piece is clarified at accidental from the bag and then replaced in the bag. A cooperate piece is then clarified at accidental. Construct a catalogue of the potential developments (for stance, RB enacts the development red piece followed by bluish piece) and use your catalogue to designate the presumption that the two pieces clarified are the similar perversion. (Hint: There are 16 potential developments.)A. 1/4         B. ¾     C. 2/16       D. 3/16

                        Possible developments:                  RR       RB       RG      RY

                                                                        BR       BB       BG      BY

                                                                        GR      GB      GG      GY

                                                                        YR      YB      YG      YY

 

                        P(two of similar perversion) = (Number of confederacys following a while similar perversion) / (Total

                                                                        compute of confederacys)

 

                        P(two of similar perversion) = 4/16 = ¼

 

10.  A committee of three tribe is to be formed. The three tribe earn be clarified from a catalogue of five potential committee parts. A incomplex accidental case of three tribe is smitten, following a whileout regaining, from the bunch of five tribe. Using the learning A, B, C, D, E to enact the five tribe, catalogue the potential cases of extent three and use your catalogue to designate the presumption that B is intervening in the case. (Hint: There are 10 potential cases.)A. 0.6         B. 0.4         C. 0.7      D. 0.8

                        Sample space:              ABC    ABD   ABE    ACD   ACE

                                                            ADE    BCD    BCE    BDE    CDE

 

                        P(confederacy includes B) = (Number of confederacys including B) / (Total

                                                                        compute of confederacys)

 

                        P(confederacy includes B) = 6/10 = 0.6

           

11.  In the leading course of rolls of a die, the compute of odd computes exceeded the compute of equal computes by 5. In the cooperate course of rolls of the similar die, the compute of odd computes exceeded the compute of equal computes by 11. Designate which course is closer to the 50/50 bearing of odd/equal forecasted of a impartially rolled die.

A. The cooperate course is closer accordingly the destruction floating odd and equal computes is important than the destruction for the leading course.

B. The leading course is closer accordingly the destruction floating odd and equal computes is hither than the destruction for the cooperate course.

C. Since 1/2 > 1/5 > 1/11, the leading course is closer.

D. The course closer to the speculative 50/50 cannot be decided equaltual the entirety compute of rolls for twain course is dedicated.

12.  Jody checked the region 12 spans on Monday, and the lacriterion digit of the region was odd six spans over than it was equal. On Tuesday, she checked it 18 spans and the lacriterion digit was odd view spans over than it was equal. Designate which course is closer to the 50/50 bearing of odd/equal forecasted of such a course of region checks.

A. The Monday course is closer accordingly 1/6 is closer to 1/2 than is 1/8.

B. The Monday course is closer accordingly 6/12 is closer to 0.5 than is 8/18.

C. The Tuesday course is closer accordingly the 13/18 is closer to 0.5 than is 9/12.

D. The course closest to the speculative 50/50 cannot be decided following a whileout shrewd the compute of odds and equals in each course.

 

            Monday: 9 odd, 3 equal           P(odd) = 9/12 = 0.75

            Tuesday: 13 odd, 5 equal         P(odd) = 13/18 ≈ 0.722 < 0.75

 

13.  Suppose you pay $1.00 to roll a impartial die following a while the mind that you earn get end $3.00 for rolling a 5 or a 2, nothing incorrectly. What is your forecasted admire?

A. $1.00           B. $0.00              C. $3.00        D. −$1.00

 

            E(x) = (1/3)($3) - $1 = $1 - $1 = $0

 

14.  On a multiple dainty criterion, each inquiry has 6 potential responses. If you construct a accidental suspect on the leading inquiry, what is the presumption that you are redress?

A. 1/5         B. 1/6         C. 1/4        D. 2/5

 

            P(correct) = Compute of redress responses / Compute of potential daintys

 

            P(correct) = 1/6

 

15.  A consider of two types of destroy killers was manufactured on two detail destroy frames. One destroy killer killed 15% over destroys than the other. This destruction was indicative at the 0.05 equalize. What does this balance?

A. The progress was due to the event that there were over destroys in one consider.

B. The presumption that the destruction was due to hazard remaining is important than 0.05.

C. The presumption that one destroy killer manufactured meliorate by hazard remaining is hither than 0.05.

D. There is not sufficient advice to construct any misrecord.

 

 

 

 

 

16.  The disposeification of B.A. disposes won by a persomal nursery is catalogueed adown, by important.

Major                    Frequency

English                 2073

Mathematics        2164

Chemistry            318

Physics                856

Liberal Arts          1358

Business              1676

Engineering          868

                             9313

What is the presumption that a accidentally clarified dispose is not in Business?

A. 0.7800          B. 0.8200         C. 0.8300         D. 0.9200

 

            P(not in Business) = (Number not in Business) / Entirety compute of disposes

 

            P(not in Business) = (9313 – 1676) / 9313

 

            P(not in Business) = 0.8200

 

17.  A 28-year-old man pays $125 for a one-year duration security cunning following a while coverage of $140,000. If the presumption that he earn speed through the year is 0.9994, to the undeviating dollar, what is the man’s forecasted admire for the security cunning?

A. $139,916        B. −$41         C. $84         D. −$124

 

            E(x) = (1 – 0.9994)($140,000) - $125 = -$41

 

 

18.  A bag contains 4 red marbles, 3 bluish marbles, and 7 unseasoned marbles. If a marble is accidentally clarified from the bag, what is the presumption that it is bluish?

A. 2/11        B. 3/11       C. 5/14        D. 3/14

 

            P(blue) = Compute of bluish marbles / Entirety compute of marbles

 

            P(blue) = 3 / (4 + 3 + 7) = 3/14

 

 

 

 

 

19.  The postulates set enacts the pay equalizes of the parts of a aver club. Admire the presumption that a accidentally clarified part earns at insignificantest $98,000.

112,000 126,000 90,000 133,000 94,000 112,000 98,000 82,000 147,000 182,000 86,000 105,000

140,000 94,000 126,000 119,000 98,000 154,000 78,000 119,000

A. 0.4         B. 0.6        C. 0.66         D. 0.7

 

            P(stipend ≥ $98,000) = Compute of salaries ≥ 98,000 / Entirety compute of salaries

 

            P(stipend ≥ $98,000) = 14/20 = 0.7

 

20.  A consider of novices gate Statistics 101 was manufactured. Impure hundred novices who premeditated for over than 10 hours averaged a B. Two hundred novices who premeditated for hither than 10 hours averaged a C. This destruction was indicative at the 0.01 equalize. What does this balance?

A. The presumption that the destruction was due to hazard remaining is important than 0.01.

B. There is hither than a 0.01 hazard that the leading bunch’s gradations were meliorate by hazard remaining.

C. The progress was due to the event that over tribe premeditated.

D. There is not sufficient advice to construct any misrecord

 

 

21.  Sample extent = 400, case balance = 44, case flag derangement = 16. What is the brink of falsity?

A. 1.4               B. 1.6               C. 2.2             D. 2.6

 

            Assuming a 95% self-reliance equalize, and noting that this assort seems to use  z = 2     for this self-reliance equalize instead of the over obsequious 1.96 admire.

 

                        E = z*s/√n = 2 * 16 / √400 = 1.6

 

 

 

22.  Select the best fit outoutsequence on the plant diagram adown.

https://study.ashworthcollege.edu/access/content/group/8ef8b2f7-197d-41de-a4c4-db81a717c013/v9/Images/Lesson%206%20Exam/MA260%20Lesson%206%20exam%20question%205.JPG

 

 

D. None of the outlines is the outoutsequence of best

 

 

23.              A researcher wishes to admire the balance equality of coin late per month on aid by households in a true vicinity. She desires a brink of falsity of $30. Past studies insinuate that a population flag derangement of $248 is temperate. Admire the restriction case extent needed to admire the population balance following a while the undoubtful closement.

A. 274        B. 284      C. 264        D. 272

 

Again, ostentatious a 95% self-reliance season, following a while z = 2.00 instead of 1.96:

 

           n = (z * s / E)2 = (2 * 248 / 30)2 = 273.35 à 274

 

24.           Suggest the producer of the interdependence floating the postulates.

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The graph pomps power of coffee (y) and compute of scoops used to construct 10 cups of coffee (x). Identify the reasonable producer of the interdependence.

 

 

A. The change in the x wavering is a frequented producer of the change in the y wavering.

 

B. There is no interdependence floating the waverings.

 

C. The interdependence is due to a beggarly underlying producer.

 

D. The interdependence floating the waverings is inventcidental

 

25.  Suggest the producer of the interdependence floating the postulates.

https://study.ashworthcollege.edu/access/content/group/8ef8b2f7-197d-41de-a4c4-db81a717c013/v9/Images/Lesson%206%20Exam/MA260%20Lesson%206%20exam%20question%2010.JPG

The graph pomps power of coffee (y) and compute of scoops used to construct 10 cups of coffee (x). Identify the reasonable producer of the interdependence.

 

A.The change in the x wavering is a frequented producer of the change in
the y wavering.

 

B. There is no interdependence floating the waverings.

 

C. The interdependence is due to a beggarly underlying producer.

 

D. The interdependence floating the waverings is inventcidental.

 

26.A population rate is to be admired. Admire the restriction case extent needed to close a brink of falsity E = 0.01following a while a 95% dispose of self-reliance.

A. 7,000           B. 8,000              C. 9,000       D. 10,000

 

     n = p(1-p)(z/E)2 = (0.5)(0.5)(2/0.01)2 = 10,000

 

27. Select the best admire of the interdependence coefficient for the postulates depicted in the plant diagram.

https://study.ashworthcollege.edu/access/content/group/8ef8b2f7-197d-41de-a4c4-db81a717c013/v9/Images/Lesson%206%20Exam/MA260%20Lesson%206%20exam%20question%208.JPG

 

A. -0.9

 

B. 0.1

 

C. 0.5

 

D. 0.9

 

        The mount of the return outoutsequence is disclaiming, so the coefficient of interdependence must

        also be disclaiming.

 

28. A case of nine novices is clarified from floating the novices gate a detail exam. The nine novices were asked how abundantly span they had late considering for the exam and the responses (in hours) were as follows:18, 7, 10, 13, 12, 16, 5, 20, 21

 

Estimate the balance consider span of all novices gate the exam. Round your response to the undeviating tenth of an hour if undoubtful.     A. 13 hours     B. 12.2 hours         C. 13.6 hours

D. It is not potential to admire the population balance from this case postulates

 

Mean = (18 + 7 + 10 + 13 + 12 + 16 + 5 + 20 + 21) / 9 = 13.6

29. The plant frame and best-fit outoutsequence pomp the pertinency floating the postulates for the cost of a hoard (y) and pursuit (x) in peremptory units. The interdependence coefficient is 0.8. Foretell the hoard cost for an pursuit admire of 6.

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A. 8.8

 

B. 6.2

 

C. 8.2

 

D. None of the admires are redress

 

    Draw a upright outoutsequence through “6” on the insipid axis, and prolong the outoutsequence uprightly until it intersects the outoutsequence on the graph. Then pull a insipid outoutsequence through the top of intersection and prolong that outoutsequence to the left until it intersects the upright axis. Recognize the admire from the upright axis, which is about 6.2.

 

 

 

 

 

 

30.The graph pomps a mete of agreement (y) and miles walked weekly. Identify the reasonable producer of the interdependence.

https://study.ashworthcollege.edu/access/content/group/8ef8b2f7-197d-41de-a4c4-db81a717c013/v9/Images/Lesson%206%20Exam/MA260%20Lesson%206%20exam%20question%204.JPG

 

A. The interdependence is inventcidental.

 

B. There is a beggarly underlying producer of the interdependence.

 

C. There is no interdependence floating the waverings.

 

D. Walking is a frequented producer of the agreement.

 

 

31. Elequal effeminate nursery novices are clarified at accidental and asked their altitudes. The altitudes (in inches) are as follows:67, 59, 64, 69, 65, 65, 66, 64, 62, 64, 62Estimate the balance hview of all effeminate novices at this nursery. Round your response to the undeviating tenth of an inch if undoubtful.

 

A. It is not potential to admire the population balance from this case postulates

 

B. 64.3 inches

 

C. 64.9 inches

 

D. 63.7 inches

 

        Mean = (67 + 59 + 64 + 69 + 65 + 65 + 66 + 64 + 62 + 64 + 62) / 11 = 64.3

32. Select the best fit outoutsequence on the plant diagram adown.

https://study.ashworthcollege.edu/access/content/group/8ef8b2f7-197d-41de-a4c4-db81a717c013/v9/Images/Lesson%206%20Exam/MA260%20Lesson%206%20exam%20question%2011.JPG

 

 

A. A

 

B. B

 

C. C

 

D. All of the outlines are equal good

 

33. In a poll of 400 voters in a true aver, 61% said that they incongruous a voter ID score that ability aloft some fairly-deduced voters from voting. The brink of falsity in the poll was reputed as 4 percentage tops (following a while a 95% dispose of self-reliance). Which averment is redress?

A. The reputed brink of falsity is accordant following a while the case extent.

B. There is not sufficient advice to designate whether the brink of falsity is accordant following a while the case extent.

C. The case extent is too insignificant to close the undoubtful brink of falsity.

D. For the dedicated case extent, the brink of falsity should be insignificanter than undoubtful

 

     Required case extent = (phat)(1 – phat)(z/E)2 = (0.61)(1 – 0.61)(2/0.04)2 = 594.75

34.The plant frame and best-fit outoutsequence pomp the pertinency floating the compute of cars indecision by a develop (y) and the equality of span following the end of assortes (x) in peremptory units. The interdependence coefficient is -0.55. Designate the equality of change in the compute of cars not explained by the change span following schhttps://study.ashworthcollege.edu/access/content/group/8ef8b2f7-197d-41de-a4c4-db81a717c013/v9/Images/Lesson%206%20Exam/MA260%20Lesson%206%20exam%20question%206.JPG

 

A. 55%

 

B. 70%

 

C. 30%

 

D. 45%

 

   Coefficient of non-vill = 1 – r2 = 1 – (-0.55)2 = 0.6975 → 70%

 

35. Which graph has two bunchs of postulates, interdependences following a whilein each bunch, but no interdependence floating all the postulates?

 

 

A.

https://study.ashworthcollege.edu/access/content/group/8ef8b2f7-197d-41de-a4c4-db81a717c013/v9/Images/Lesson%206%20Exam/MA260%20Lesson%206%20exam%20question%203%20_A_.JPG

 

 

B.

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C.

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D

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36. The plant frame and best-fit outoutsequence pomp the pertinency floating the compute of cars indecision by a develop (y) and the equality of span following the end of assortes (x) in peremptory units. The interdependence coefficient is -0.55. Use the outoutsequence of best fit to foretell the compute of cars at span 4 following the end of assortes.

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A. 7.0

 

B. 6.0

 

C. 8.0

 

D. 3.5

 

Draw a upright outoutsequence through the admire 4 on the insipid axis and prolong the outoutsequence uprightly until it intersects the outoutsequence pompn on the graph. Then pull a insipid outoutsequence through the top of intersection and prolong it to the left until it intersects the upright axis. Recognize the admire where the insipid outoutsequence crosses the upright axis. The admire is almost 7.

 

37. A researcher wishes to admire the rate of nursery novices who deceit on exams. A poll of 560 nursery novices pomped that 27% of them had, or prepared to, deceit on examinations. Find the 95% self-reliance season.

A. 0.2323 to 0.3075

B. 0.2325 to 0.3075

C. 0.2325 to 0.3185

D. 0.2323 to 0.3185

 

      Lower season = phat – z*sqrt(phat*(1 – phat)/n)

      Lower season = 0.27 – 2*sqrt(0.27*0.73/560)

      Lower season = 0.2325

 

      Upper season = phat+ z*sqrt(phat*(1 – phat)/n)

      Upper season = 0.27 + 2*sqrt(0.27*0.73/560)

      Upper season = 0.3075

 

 

 

 

 

 

 

38. Floating a accidental case of 150 employees of a detail association, the balance substitute interval is 29.6 miles. This balance lies 1.2 flag derangements aloft the balance of the sampling disposeification. If a cooperate case of 150 employees is clarified, what is the presumption that for the cooperate case, the balance substitute interval earn be hither than 29.6 miles?

A. 0.8849           B. 0.5          C. 0.1131        D. 0.1151

 

    P(cooperate case balance ≤ 29.6) = P(z ≤ 1.2) = 0.8849

 

39. The plant frame and best-fit outoutsequence pomp the pertinency floating the cost per part (y) and the availability of that part (x) in peremptory units. The interdependence coefficient is -0.95. Designate the equality of change in pricing explained by the change in availability.

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A. 5%

 

B. 10%

 

C. 95%

 

D. 90%

 

    Coefficient of vill = r2 = (-0.95)2 = 0.9025 ≈ 90%

 

40. Of the 6796 novices in one develop boundary, 1537 cannot recognize up to gradation equalize. Floating a case of 812 of the novices from this develop boundary, 211 cannot recognize up to gradation equalize. Find the case rate of novices who cannot recognize up to gradation equalize       A. 0.14        B. 0.26      C. 211      D. 0.23

 

phat = x/n = 211 / 812 = 0.26