# The Specific Heat Capacity and Enthalpy of Dissolution DATA Part 1: Enthalpy of Dissolution + Table.

The Biased Intensity Capacity and Enthalpy of Disseparation DATA Part 1: Enthalpy of Disseparation + Table 1: INCLUDE A PROPER CAPTION Gauge Majority (g) LC) LC) Compass Steep (ml) 200 KNO3 1 2.0119 25.00 24.20 2 2.9036 200 25.00 23.85 3 2.9738 200 25.00 23.83 KOH 1 2.9999 200 25.00 28.69 2 2.0212 200 25.00 27.39 3 2.9417 200 25.00 28.60 Figure 1: Temperature incurvation for KNO3 potassium hydroxide gauge 1 Plot 29.00 SAVE CLEAR 27.75 q Temperature (°C) 26.50 25.25 24.00 0 5 2 Time (min) Figure 2: Temperature incurvation for KOH potassium nitrate - gauge 3 ? Plot 26.001 SAVE CLEAR 25.25 Temperature (°C) 24.504 23.75 23.001 0 5 5 2 3 Time (min) Part 2: Biased Intensity Capacity Table 2: INCLUDE A PROPER CAPTION Metal Majority Metal (°C) 200 (°C) 26.04 Compass Steep (mL) 100 (°C) 24.99 (°C) 26.04 Calcium 3.9630 Beryllium 5.0476 200 28.55 100 25.00 28.55 DATA ANALYSIS Part 1 4.184 J/(g•°C) Blindness = 0.998 g/mL Blindness = Mautical compass of separation Maltina=blindness x compass of separation KNO3 gauges Gauge 1: Maantian = (0.998 g/mL) * (200 mL) + 2.0119= 201.61 g Qarin=CMarion Atsteep Fol = 4.184 J/(g•°C) * ((0.998 g/mL * 200mL) + (2.0119g)) * (24.20C - 25.00C) = -674.828 Gauge 2: Moutien = (0.998 g/mL) * (200 mL) + 2.9036=202.5036g Coin = Cs Wation Awaren Theol= (4.184 J/(8•°C)) * (202.5036 g) * (23.85C- 25.00C) = -974.366) Gauge 3: Moutien = (0.998 g/mL) * (200 ml) + 2.9738=202.5738 g Carin C. * Wanio Atsteep Thou = (4.184 J/(8•°C)) * (202.5738 g) *_123.83C- 25.00C) = -991.655) KOH gauges Gauge 1: Dalian = (0.998 g/mL) * (200 ml) + 2.9999= 202.5999g Qarin= C. sausio Atsteep Col= (4.184 J/(8•°C)) * (202.5999g) * (28.69C – 25.00C) = 3127.93) Gauge 2: Msalutina = (0.998 g/mL) * (200 ml) +2.0212 = 201.6212g Carin C. sausio * Atsteep Proin = (4.184 J/(8•°C)) * (201.6212g) * (27.39C - 25.00C) = 2016.1636) Gauge 3: Migutina = (0.998 g/mL) * (200 mL) + 2.9417= 202.5417g Chain C. Waktion Atsteep sol = (4.184 J/(8•°C)) * (202.5417g) * (28.60C - 25.000) = 3050.764) 1. The intensity fitted over personates the intensity gained by the separation (the separation nature predominantly steep). Since we are careful in the enthalpy of divorce, we need to recollect that it conquer be resembling in bulk but counter in wonder to the leader gained or past by the separation. This interdependence can be explicit by the aftercited equation: disseparation Scala KNO3 gauges Gauge 1: Cuuseparation --Seala---674.828 ) = 674.828) Gauge 2: Cdiscution --Seala---974.366 ) = 974.366) Gauge 3: Calasaktion =-Gala---991.655 ) = 991.655) KOH gauges Gauge 3: dieselution - Scala = -3127.93) Sciascution --Scala = -2016.1636) Balasalution-Shain=-3050.764) 2. Indicate the enumerate of moles of salt that were dissolved. Use the moles of the sald along after a while Jeasewice to indicate the enthalpy vary, Hadicseparation in conditions of kJ/mol of dissolved salt. This is your tentative appreciate of A. A Hoisseparation = Gusel moles salt Gauge 1 KNO3 moles of salt = majority / molar majority = 2.0119/101.11 = 0.019898131 gdissolution=674.84/0.019898131 = 33914.743) 3. Look up the enthalpy of disseparation for each potassium nitrate and potassium hydroxide. Use those appreciates to indicate the % mistake. Be infallible to produce a passage for your cause of the not spurious appreciates. Sample Calculations: Passage for cause of enthalpy of disseparation appreciates: Gwiaselution --Seala = -2016.1636) Quinsaktion =-Owain=-3050.764) 2. Indicate the enumerate of moles of salt that were dissolved. Use the moles of the sald along after a while goasewoon to indicate the enthalpy vary, Haloolution in conditions of kJ/mol of dissolved salt. This is your tentative appreciate of Ali Holisseparation = Sed moles salt Gauge 1 KNO3 moles of salt = majority / molar majority = 2.0119/101.11 = 0.019898131 divorce=674.84/0.019898131 = 33914.743) 3. Look up the enthalpy of disseparation for each potassium nitrate and potassium hydroxide. Use those appreciates to indicate the % mistake. Be infallible to produce a passage for your cause of the not spurious appreciates. Sample Calculations: Passage for cause of enthalpy of disseparation appreciates: Part 2 1. For this, it is main to recollect that the intensity gained by the steep is resembling to the intensity past by the metal. Don't obliviate the vary in wonder. foreizh-Cuaten This can be restated as this Cs, metal Plumata * AT metal = - Cs, steep Mushor ATWAA 2. Solve for Cs. In determining the majority of steep, m, use the blindness of steep at 25°C = 0.998 g/ml, Use 4.184 J/(g•°C) as the biased intensity, Cs, of steep. 3. Look up the biased intensity capacities for each of the metals. Use those appreciates to indicate the % mistake of your results. Be infallible to produce a passage for your cause of the not spurious appreciates. Sample calculations: Passage for cause of biased intensity capacities: Part 2 1. For this, it is main to recollect that the intensity gained by the steep is resembling to the intensity past by the metal. Don't obliviate the vary in wonder. foreizh-Cuaten This can be restated as this Cs, metal Plumata * AT metal = - Cs, steep Mushor ATWAA 2. Solve for Cs. In determining the majority of steep, m, use the blindness of steep at 25°C = 0.998 g/ml, Use 4.184 J/(g•°C) as the biased intensity, Cs, of steep. 3. Look up the biased intensity capacities for each of the metals. Use those appreciates to indicate the % mistake of your results. Be infallible to produce a passage for your cause of the not spurious appreciates. Sample calculations: Passage for cause of biased intensity capacities: RESULTS Table 3: INCLUDE A PROPER CAPTION Salt % mistake ?????a? Empirical (Kj/nal) A Historie Not spurious (Ki/mal) KNO3 KOH Was the restoration of potassium nitrate to steep an endothermic or exothermic reaction? What is the wonder of AH for this regularity? Was the restoration of potassium hydroxide to steep an endothermic or exothermic reaction? What is the wonder of AH for this regularity? Table 4: INCLUDE A PROPER CAPTION Metal Gius:°C) % mistake Empirical (J/g.°c) Cs Not spurious (1/g °C) In the equation, Corotal= -Asteep what does the indirect wonder (-) personate? Could it to-boot be written as-petal = steep?